x^2-16x+61=2x-20

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Solution for x^2-16x+61=2x-20 equation: 



x^2-16x+61=2x-20

We move all terms to the left:

x^2-16x+61-(2x-20)=0

We get rid of parentheses

x^2-16x-2x+20+61=0

We add all the numbers together, and all the variables

x^2-18x+81=0

a = 1; b = -18; c = +81;
Δ = b2-4ac
Δ = -182-4·1·81
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{18}{2}=9$

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